Belajar IP Management (Catatan)
172.31.100.255/20
a. What is the class IP of the numbers?
Class B -> Class Full 16 bits
b. How many network bits are there ?
Network bits -> 20 Bits
c. How many host bits are there ?
Host bits -> (32-20) -> 12 Bits
D. How many host bits borrowed?
Host bits borrowed = Network Bits - Class Full = 20 - 16 = 4 bits
E. How many available subnet ?
Available Subnet -> 2 pangkat n -> n = Borrowed Bits
2 pangkat 4 -> 16
F. How many available host ?
Available host -> 2n - 2 -> n = Host Bits
2 pangkat 12 - 2 = 4094
G. Subnet mask
20 -> 255.255.240.0
H. How many interval for each subnet ?
Interval 16
I. What is the subnet address for the numbers ?
Subnet Address
/20 -> Octet ke 3
interval 16 terdekat dengan 100 - > 96
network ip -> 172.31.96.0 /20
J. What is the broadcast address for the numbers ?
Broadcast Address
172.31.100.255 /20 network selanjutnya
172.31.112.0 /20
berarti broadcastnya
172.31.111.255 /20
K. What are the available hosts ?
available hosts -> 4094
antara : network dengan broadcastnya
172.31.100.255 /20
172.31.112.0 /20
172.31.111.255 /20
L. What are the available hosts for the second subnet ?
172.31.16.0 /20
Broadcast 172.31.31.255 /20
M. Is it public IP Addresses -or- private IP Addresses ?
Private IP Address
N. Define the number! (Is it Unicast Address? Network Address? -or- Broadcast Address?)
Unicast Address
Description » Belajar IP Management
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172.31.100.255/20
a. What is the class IP of the numbers?
Class B -> Class Full 16 bits
b. How many network bits are there ?
Network bits -> 20 Bits
c. How many host bits are there ?
Host bits -> (32-20) -> 12 Bits
D. How many host bits borrowed?
Host bits borrowed = Network Bits - Class Full = 20 - 16 = 4 bits
E. How many available subnet ?
Available Subnet -> 2 pangkat n -> n = Borrowed Bits
2 pangkat 4 -> 16
F. How many available host ?
Available host -> 2n - 2 -> n = Host Bits
2 pangkat 12 - 2 = 4094
G. Subnet mask
20 -> 255.255.240.0
H. How many interval for each subnet ?
Interval 16
I. What is the subnet address for the numbers ?
Subnet Address
/20 -> Octet ke 3
interval 16 terdekat dengan 100 - > 96
network ip -> 172.31.96.0 /20
J. What is the broadcast address for the numbers ?
Broadcast Address
172.31.100.255 /20 network selanjutnya
172.31.112.0 /20
berarti broadcastnya
172.31.111.255 /20
K. What are the available hosts ?
available hosts -> 4094
antara : network dengan broadcastnya
172.31.100.255 /20
172.31.112.0 /20
172.31.111.255 /20
L. What are the available hosts for the second subnet ?
172.31.16.0 /20
Broadcast 172.31.31.255 /20
M. Is it public IP Addresses -or- private IP Addresses ?
Private IP Address
N. Define the number! (Is it Unicast Address? Network Address? -or- Broadcast Address?)
Unicast Address
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